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(P)=-0.125P^2+10P-70
We move all terms to the left:
(P)-(-0.125P^2+10P-70)=0
We get rid of parentheses
0.125P^2-10P+P+70=0
We add all the numbers together, and all the variables
0.125P^2-9P+70=0
a = 0.125; b = -9; c = +70;
Δ = b2-4ac
Δ = -92-4·0.125·70
Δ = 46
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{46}}{2*0.125}=\frac{9-\sqrt{46}}{0.25} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{46}}{2*0.125}=\frac{9+\sqrt{46}}{0.25} $
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